Sampling distributions and the central limit theorem

03/31/2021

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Outline

  • The following topics will be covered in this lecture:

    • Random samples
    • Sampling distributions
    • Point estimators
    • Central limit theorem
    • Applications of the central limit theorem
    • Approximate sampling distribution of a difference in sample means

Motivation

  • We have now learned about the fundamentals of theoretical probabilistic models.

  • Particularly, we have learned about the:

    • probability distribution;
    • probability mass / density function; and
    • cumulative probability distribution function;
  • for discrete and continuous random variables.

  • We have also learned about several fundamental probability distributions:

    • the binomial;
    • the uniform; and
    • the normal.
  • We will begin to combine these models with data to produce statistical inference.

  • Our goal in this course is to use statistics from a small, representative sample to say something general about the larger, unobservable population or phenomena.

  • The process of saying something general from the smaller representative sample, while qualifying our uncertainty, is what we mean by statistical inference.

Motivation continued

  • The link between the probability models in the earlier chapters and the data is made as follows.

  • Suppose we take a sample of \( n = 10 \) observations \( \{x_{1,i}\}_{i=1}^{10} \) from a population and compute the sample average,

    \[ \overline{x}_1 = \frac{1}{n} \sum_{i=1}^n x_{1,i} = \frac{1}{10}\sum_{i=1}^{10} x_{1,i} \]

    getting the result \( \overline{x}_1 = 10.2 \).

  • Now we repeat this process, taking a second sample of \( n = 10 \) observations from the same population,

    \[ \{x_{2,i}\}_{i=1}^{10} \]

    and the resulting sample average is \( \overline{x}_2=10.4 \).

  • This discrepancy is what we call sampling error, in which the random variation in a sample of a fixed size \( n \) upon replication produces differences in the computation of a statistic.

  • The sample average depends on the observations in the sample, which differ from sample to sample because they are random variables.

  • Consequently, the sample average (or any other function of the sample data) is a random variable.

  • Because a statistic is a random variable, it has a probability distribution.

Motivation continued

  • Specifically, suppose that we want to obtain an estimate of a population parameter, where the population is modeled with a random variable \( X \).

  • We know that before the data are collected, the observations are considered to be random variables,

    • i.e., we treat an independent sequence of measurements of \( X \),

    \[ X_1, X_2, \cdots , X_n \]

    • as random variables all drawn from a parent distribution \( X \sim F(x) \) (where the CDF will define the distribution).
    Random sample
    The random variables \( X_1 , X_2, \cdots , X_n \) are a random sample of size \( n \) if the \( X_i \)’s are independent random variables and every \( X_i \) has the same probability distribution.
  • We then say that the measurements we obtain are possible outcomes of the sample variables \( \{X_i\}_{i=1}^n \); particularly, if we make a computation of the sample mean,

    \[ \overline{X} = \frac{1}{n} \sum_{i=1}^n X_i \]

    the above is treated as a random variable (a linear combination of random variables) which has a random outcome, dependent on the realizations of the \( X_i \).

Motivation continued

  • More generally, any function of the observations, i.e., any statistic, is also modeled as a random variable.

  • If \( h \) is a general function used to compute some statistic, we thus define

    \[ \tilde{X} = h(X_1, \cdots, X_n) \]

    to be a random variable that will depend on the particular realizations of \( X_1,\cdots, X_n \).

  • We call the probability distribution of a statistic a sampling distribution.

    Sampling Distribution
    The probability distribution of a statistic is called a sampling distribution.

Motivation continued

  • Given particular realizations of the sample random variables, we obtain a fixed numerical value.

  • Each numerical value in a data set is treated as the observed realization of a random variable.

  • Given particular realizations \( x_1,\cdots,x_n \) of the random variables \( X_1, \cdots, X_n \), the value

    \[ \overline{x} = \frac{1}{n}\sum_{i=1}^n x_i \]

    is not a random variable, as this is a fixed numerical value.

  • Given some particular, observed realizations \( x_1, \cdots,x_n \),

    \[ \tilde{x} = h(x_1, \cdots, x_n) \]

    is a fixed numerical value, based on the fixed, observed data values \( x_1, \cdots, x_n \).

Motivation continued

  • When discussing inference problems, it is convenient to have a general symbol to represent the parameter of interest – we use the Greek symbol \( \theta \) (theta) to represent the parameter.

  • The symbol \( \theta \) can represent the mean \( \mu \), the variance \( \sigma^2 \), or any parameter of interest to us.

  • The objective of point estimation is to estimate a single number based on sample data that is the most plausible value for \( \theta \).

  • The numerical value of a sample statistic is used as the point estimate.

  • Once we describe the process of point estimation, the next step is to describe how we quantify the uncertainty of the estimate.

  • If \( X \) is a random variable with probability distribution \( F(x) \), characterized by the unknown parameter \( \theta \),

    and if \( X_1 , X_2, \cdots , X_n \) is a random sample of size \( n \) from \( X \),

  • the statistic \( \hat{\Theta} = h(X_1 , X_2 , ... , X_n ) \) given as a function of the sample is called a point estimator of \( \theta \).

  • Note that \( \hat{\Theta} \) is a random variable because it is a function of random variables.

  • After the sample has been selected, \( \hat{\Theta} \) takes on a particular numerical value \( \hat{\Theta} \) called the point estimate of \( \theta \).

  • The uncertainty of the point estimate \( \hat{\Theta} \) can be understood as how much will the sampling error cause a discrepancy between \( \hat{\Theta} \) and the true \( \theta \).

Point estimators

  • We will now introduce some formal definitions:
  • Point estimators
    A point estimate of some population parameter \( \theta \) is a single numerical value \( \hat{\Theta} \) of a statistic \( \hat{\Theta} \). This is a particular realization of the random variable \( \hat{\Theta} \), viewed as a random variable; \( \hat{\Theta} \) is called the point estimator.
  • Estimation problems modeled as above occur frequently in engineering.

  • We often need to estimate

    • The mean \( \mu \) of a single population
    • The variance \( \sigma^2 \) (or standard deviation \( \sigma \)) of a single population
    • The proportion \( p \) of items in a population that belong to a class of interest
    • The difference in means of two populations, \( \mu_1 - \mu_2 \)
    • The difference in two population proportions, \( p_1 − p_2 \)

Point estimators continued

  • Reasonable point estimates of these parameters are as follows:

    • For \( \mu \),
      • the estimate is \( \hat{\mu}=\overline{x} \), the sample mean.
    • For \( \sigma^2 \),
      • the estimate is \( \hat{\sigma}^2 = s^2 \), the sample variance.
    • For \( p \),
      • the estimate is \( \hat{p}=\frac{x}{n} \), the sample proportion, where \( x \) is the number of items in a random sample of size \( n \) that belong to the class of interest.
    • For \( \mu_1 -\mu_2 \),
      • the estimate \( \hat{\mu}_1 - \hat{\mu}_2 = \overline{x}_1 - \overline{x}_2 \), the difference between the sample means of two independent random samples.
    • For \( p_1 − p_2 \) ,
      • the estimate is \( \hat{p}_1 - \hat{p}_2 \) , the difference between two sample proportions computed from two independent random samples.
  • Generally, however, we may have several different choices for the point estimator of a parameter.

  • To decide which point estimator of a particular parameter is the best one to use, we need to examine their statistical properties and develop some criteria for comparing estimators.

Central limit theorem

  • Let's consider a simple argument for the sampling distribution of the sample mean \( X \).

  • Suppose that a random sample of size \( n \) is taken from a normal population with mean \( \mu \) and variance \( \sigma^2 \).

  • By definition of a random sample each observation in this sample, say, \( X_1, X_2, \cdots, X_n \), is a normally and independently distributed random variable with mean \( \mu \) and variance \( \sigma^2 \).

  • A special property of the normal distribution is that it can be translated and rescaled while remaining normal;

    • similarly, a sum of independent, normally distributed random variables are also normally distributed.
  • We conclude that the sample mean

    \[ \overline{X}= \frac{X_1 + X_2 + \cdots + X_n}{n} \]

    has a normal distribution with mean

    \[ \mu_\overline{X} = \frac{\mu + \mu + \cdots + \mu}{n} = \mu \]

    • and variance

    \[ \sigma^2_\overline{X} = \frac{\sigma^2 + \sigma^2 + \cdots + \sigma^2}{n^2} = \frac{\sigma^2}{n} \]

Central limit theorem continued

  • More generally, if we are sampling from a population that has an unknown probability distribution, the sampling distribution of the sample mean will still be approximately normal with mean \( \mu \) and variance \( \frac{\sigma^2}{n} \) if the sample size \( n \) is large.

  • This is one of the most useful theorems in statistics, called the central limit theorem:

    The central limit theorem
    Let \( X_1 , X_2 , \cdots , X_n \) be a random sample of size \( n \) taken from a population with mean \( \mu \) and finite variance \( \sigma^2 \) and \( \overline{X} \) be the sample mean. Then the limiting form of the distribution of \[ Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}} \] as \( n \rightarrow \infty \) is the standard normal distribution.
  • Put another way, for \( n \) sufficiently large, \( \overline{X} \) has approximately a \( N\left(\mu, \frac{\sigma^2}{n}\right) \) distribution – this says the following.

    • Suppose we take a sample of size \( n \) and compute the sample mean \( \overline{X} \).
    • Then suppose we replicate this sample and record the observed realizations for the sample mean \( \overline{x}_1, \overline{x}_2, \cdots \).
    • If the sample size \( n \) is lage, these data points \( \overline{x}_1, \cdots \) will be approximately bell shaped with the following properties:
      • the bell will be centered approximately at \( \mu \), the true population mean;
      • the spread of the data around the center will be given by approximately by the standard deviation \( \frac{\sigma}{\sqrt{n}} \).
    • Particularly, if \( n \) is very large, the observed sample means will be very close to the center (the true mean).

Central limit theorem continued

  • As a visualization of the concept, suppose again that we have a random sample indexed by \( j \) \[ X_{j,1}, \cdots, X_{j,n}. \]
  • We will make replications for \( j=1,\cdots,m \) and get a random variable for sample mean indexed by \( j \), \[ \overline{X}_j = \frac{1}{n}\sum_{i=1}^n X_{j,i}. \]
  • When we observe a realization of \( \overline{X}_j=\overline{x}_j \) or respectively the sample \[ X_{j,1}=x_{j,1}, \cdots, X_{j,n}=x_{j,n}, \] we record these fixed numerical values.
Central limit theorem

Courtesy of Mathieu ROUAUD, CC BY-SA 4.0, via Wikimedia Commons

  • The measurements \( X_{j,i} \) may be distributed according to any underlying distribution with mean \( \mu \) and standard deviation \( \sigma \).
  • However, if \( n \) is large, the \( \overline{X}_j \) is approximately normal with mean \( \mu \) and standard deviation \( \frac{\sigma}{\sqrt{n}} \).
  • The sample mean data from given realizations \( x_{i,j} \), \( \overline{x}_j \), will have approximately a bell shaped frequency, centered approximately at \( \mu \).
  • The spread of the data will be approximately \( \frac{\sigma}{\sqrt{n}} \).
  • Particularly, as \( n\rightarrow \infty \), the spread shrinks to zero, so that we get a better and better estimate (more peaked bell shape) with large sample sizes.

Central limit theorem continued

  • The central limit theorem is the underlying reason why many of the random variables encountered in engineering and science are normally distributed.

  • The observed variable results from a series of underlying disturbances that act together to create a central limit effect.

    • This can be thought in terms of the sum of random disturbances averaged over a time interval will have an average effect like a normal variable.
  • It is important, however, to consider when the sample size large enough so that the central limit theorem can be assumed to apply.

  • The answer depends on how close the underlying distribution is to the normal:

    • if the underlying distribution is normal, any sample size will work;
    • if the underlying distribution is symmetric and unimodal (not too far from normal), the central limit theorem will apply for sample sizes as low as 4 or 5.
    • if the sampled population is very nonnormal, if the sample size is greater than 30, the central limit theorem will usually apply; however, there are exceptions to this guideline.

Applications of central limit theorem

  • Suppose an electronics company manufactures resistors that have a mean resistance of \( \mu=100 \) ohms and a standard deviation of \( \sigma=10 \) ohms.
  • We will assume that the distribution of resistance is normal, (i.e., the sampling distribution of the sample mean is automatically normal).
    • I.e., the distribution for \( \overline{X} \) is the normal with mean, \[ \mu_\overline{X} = \mu = 100 \] and standard deviation \[ \sigma_\overline{X} = \frac{\sigma}{\sqrt{n}} = \frac{10}{\sqrt{n}}. \]
  • Suppose we want to find the probability that a random sample of \( n = 25 \) resistors will have an average resistance of fewer than \( 95 \) ohms.
  • Notice that for a sample size of \( n=25 \), the sampling distribution for \( \overline{X} \) is given by the normal with mean \( \mu=100 \) and standard deviation \( \frac{10}{5}=2 \).
Sampling distribution.

Courtesy of Montgomery & Runger, Applied Statistics and Probability for Engineers, 7th edition

  • Let's consider how to compute this probability in R.

Application of central limit theorem continued

  • Recall, we are trying to compute

    \[ P\left(\overline{X} < 95\right) \]

    where \( \overline{X} \) is normally distributed with \( \mu_\overline{X}=100 \) and \( \sigma_\overline{X}=2 \).

  • We can compute the standard normal z-scores as

    \[ \frac{95-100}{2} = -2.5 \]

  • In R, we can use the pnorm from last time to compute

pnorm(-2.5)
[1] 0.006209665

Application of central limit theorem continued

  • Let's note that pnorm also has alternative settings that allow us to make the probability computation for a general normal.

  • pnorm can use keyword arguments mean and sd standing for the mean and standard deviation respectively.

  • Setting these values determines the normal distribution, so that we can compute the earlier probability directly as follows:

pnorm(95, mean=100, sd=2)
[1] 0.006209665
pnorm(-2.5)
[1] 0.006209665
  • The above demonstrates the equivalence of the approaches.

  • Generally, computing this directly is preferable so that we don't make errors in computing the z-score by hand.

  • This example shows that if the distribution of resistance is normal with mean \( \mu=100 \) ohms and standard deviation of \( \sigma=10 \) ohms, finding a random sample of resistors with a sample mean less than \( 95 \) ohms is a rare event.

  • If this actually happens, it casts doubt as to whether the true mean is really \( 100 \) ohms or if the true standard deviation is really \( 10 \) ohms.

  • We will come back to this idea when we introduce hypothesis testing.

Application of central limit theorem continued

  • Suppose that a random variable X has a continuous uniform distribution with density \[ f (x) = \begin{cases} 1∕2 & 4 ≤ x ≤ 6\\ 0 & \text{else} \end{cases} \]
  • We will find the distribution of the sample mean of a random sample of size \( n = 40 \).
    • Notice, the sample size \( n>30 \) and this is a unimodal distribution, so the central limit theorem will give a good approximation.
  • The mean and variance of \( X \) are \( \mu = 5 \) and \( \sigma^2 = \frac{(6 − 4)^2}{12} = 1/3 \).
  • The central limit theorem indicates that the distribution of \( X \) is approximately normal with mean \( \mu_X = 5 \) and variance \[ σ^2_\overline{X} = \frac{\sigma^2}{n} = \frac{1/3}{40} = \frac{1}{120}. \]
  • This says that the distribution for \( \overline{X} \) from the above uniform with a sample size \( n=40 \) will be extremely peaked at the mean \( \mu \).
Sampling distribution.

Courtesy of Montgomery & Runger, Applied Statistics and Probability for Engineers, 7th edition

Approximate sampling distribution of a difference in sample means

  • We will finally consider the case in which we have two independent populations.

  • Let the first population have mean \( \mu_1 \) and variance \( \sigma^2_1 \) and the second population have mean \( \mu_2 \) and variance \( \sigma^2_2 \).

  • Suppose that both populations are normally distributed.

  • Linear combinations of independent normal random variables follow a normal distribution, so that \( X_1 - X_2 \) is also normal.

  • Suppose that \( \overline{X}_1 \) is the sample mean for the distribution of \( X_1 \) with a sample size \( n_1 \);

    • similarly, suppose that \( \overline{X}_1 \) is the sample mean for the distribution of \( X_1 \) with a sample size \( n_2 \).
  • Then, the sampling distribution of \( \overline{X}_1 − \overline{X}_2 \) is also normal with mean and variance

    \[ \begin{align} \mu_{\overline{X}_1 - \overline{X}_2} &= \mu_{\overline{X}_1} - \mu_{\overline{X}_2} = \mu_{X_1} - \mu_{X_2}\\ \sigma^2_{\overline{X}_1 - \overline{X}_2} &= \sigma^2_{\overline{X}_1} - \sigma^2_{\overline{X}_2} = \frac{\sigma^2_{X_1}}{n_1} - \frac{\sigma^2_{X_2}}{n_2}\\ \end{align} \]

  • That is to say, we have a normal model for the difference of the two samples from two independent populations;

    • in particular, the mean difference and the standard deviation of the difference can be computed like with the central limit theorem.

Approximate sampling distribution of a difference in sample means continued

  • More generally, we can use the above argument as an approximation when the sample size is large, i.e., usually when \( n>30 \).

    Approximate sampling distribution of a difference in sample means
    Suppose we have two independent populations with means \( \mu_1 \) and \( \mu_2 \) and variances \( \sigma_1^2 \) and \( \sigma_2^2 \) and if \( \overline{X}_1 \) and \( \overline{X}_2 \) are the sample means of two independent random samples of sizes \( n_1 \) and \( n_2 \) from these populations. Then the sampling distribution of \[ \begin{align} Z = \frac{\overline{X}_1 − \overline{X}_2 − (\mu_1 − \mu_2)}{\sigma_1^2/n_1 + \sigma_2^2 ∕n_2} \end{align} \] is approximately standard normal if the conditions of the central limit theorem apply. If the two populations are normal, the sampling distribution of \( Z \) is exactly standard normal.
  • To put this another way, we say that \( \overline{X}_1 - \overline{X}_2 \) has approximately a normal distribution with mean and variance

    \[ \begin{align} \mu_{\overline{X}_1 - \overline{X}_2} &= \mu_{X_1} - \mu_{X_2}\\ \sigma^2_{\overline{X}_1 - \overline{X}_2} &= \frac{\sigma^2_{X_1}}{n_1} - \frac{\sigma^2_{X_2}}{n_2}\\ \end{align} \]

    so that with technology, we can compute the probability directly (without z-scores).

  • To compute the probability of \( \overline{X}_1 - \overline{X}_2 \) being in some range, we can use pnorm with the appropriate parameters for mean and sd given as keyword arguments.